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The 1860 United States presidential election in New Jersey took place on November 6, 1860, as part of the 1860 United States presidential election. Voters chose seven electors of the Electoral College, who voted for president and vice president.
The winner in New Jersey depends on the votes. For the electoral votes, it was split, with Republican candidate Abraham Lincoln carrying four electoral votes, while Democratic candidate Stephen A. Douglas carried three. In the popular vote, Douglas won it by a narrow margin of 3.74%.
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